$$y = \frac { 1 } { ( x ^ { 2 } + 3 ) ^ { 2 } }$$
$x=-\frac{\sqrt{-3\sqrt{y}+1}}{\sqrt[4]{y}}$
$x=\frac{\sqrt{-3\sqrt{y}+1}}{\sqrt[4]{y}}\text{, }y>0\text{ and }y\leq \frac{1}{9}$
$y=\frac{1}{\left(x^{2}+3\right)^{2}}$
