How to solve y=(10)/(3)x-12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve y=(10)/(3)x-12 | Equatix

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$$y= \frac{ 10 }{ 3 } x-12$$

$x=\frac{3\left(y+12\right)}{10}$

Swap sides so that all variable terms are on the left hand side.

$$\frac{10}{3}x-12=y$$

Add $12$ to both sides.

$$\frac{10}{3}x=y+12$$

Divide both sides of the equation by $\frac{10}{3}$, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{10}{3}x}{\frac{10}{3}}=\frac{y+12}{\frac{10}{3}}$$

Dividing by $\frac{10}{3}$ undoes the multiplication by $\frac{10}{3}$.

$$x=\frac{y+12}{\frac{10}{3}}$$

Divide $y+12$ by $\frac{10}{3}$ by multiplying $y+12$ by the reciprocal of $\frac{10}{3}$.

$$x=\frac{3y}{10}+\frac{18}{5}$$

$y=\frac{10x}{3}-12$