How to solve y=(13-x)/(2)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve y=(13-x)/(2) | Equatix

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$$y= \frac{ 13-x }{ 2 }$$

$x=13-2y$

Divide each term of $13-x$ by $2$ to get $\frac{13}{2}-\frac{1}{2}x$.

$$y=\frac{13}{2}-\frac{1}{2}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{13}{2}-\frac{1}{2}x=y$$

Subtract $\frac{13}{2}$ from both sides.

$$-\frac{1}{2}x=y-\frac{13}{2}$$

Multiply both sides by $-2$.

$$\frac{-\frac{1}{2}x}{-\frac{1}{2}}=\frac{y-\frac{13}{2}}{-\frac{1}{2}}$$

Dividing by $-\frac{1}{2}$ undoes the multiplication by $-\frac{1}{2}$.

$$x=\frac{y-\frac{13}{2}}{-\frac{1}{2}}$$

Divide $y-\frac{13}{2}$ by $-\frac{1}{2}$ by multiplying $y-\frac{13}{2}$ by the reciprocal of $-\frac{1}{2}$.

$$x=13-2y$$

$y=\frac{13-x}{2}$