How to solve y=(3)/(2)(x-1)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve y=(3)/(2)(x-1) | Equatix

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$$y= \frac{ 3 }{ 2 } (x-1)$$

$x=\frac{2y}{3}+1$

Use the distributive property to multiply $\frac{3}{2}$ by $x-1$.

$$y=\frac{3}{2}x-\frac{3}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{2}x-\frac{3}{2}=y$$

Add $\frac{3}{2}$ to both sides.

$$\frac{3}{2}x=y+\frac{3}{2}$$

Divide both sides of the equation by $\frac{3}{2}$, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}x}{\frac{3}{2}}=\frac{y+\frac{3}{2}}{\frac{3}{2}}$$

Dividing by $\frac{3}{2}$ undoes the multiplication by $\frac{3}{2}$.

$$x=\frac{y+\frac{3}{2}}{\frac{3}{2}}$$

Divide $y+\frac{3}{2}$ by $\frac{3}{2}$ by multiplying $y+\frac{3}{2}$ by the reciprocal of $\frac{3}{2}$.

$$x=\frac{2y}{3}+1$$

$y=\frac{3\left(x-1\right)}{2}$