Solve of parallel and lines ADB y= -5 9 x+ 1 6 - Line e is and write it as a proper fraction , in | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$y = \frac { - 5 } { 9 } x + \frac { 1 } { 6 }$$

Solve for x

$x=-\frac{9y}{5}+\frac{3}{10}$

Steps for Solving Linear Equation

Fraction $\frac{-5}{9}$ can be rewritten as $-\frac{5}{9}$ by extracting the negative sign.

$$y=-\frac{5}{9}x+\frac{1}{6}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{5}{9}x+\frac{1}{6}=y$$

Subtract $\frac{1}{6}$ from both sides.

$$-\frac{5}{9}x=y-\frac{1}{6}$$

Divide both sides of the equation by $-\frac{5}{9}$, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{5}{9}x}{-\frac{5}{9}}=\frac{y-\frac{1}{6}}{-\frac{5}{9}}$$

Dividing by $-\frac{5}{9}$ undoes the multiplication by $-\frac{5}{9}$.

$$x=\frac{y-\frac{1}{6}}{-\frac{5}{9}}$$

Divide $y-\frac{1}{6}$ by $-\frac{5}{9}$ by multiplying $y-\frac{1}{6}$ by the reciprocal of $-\frac{5}{9}$.

$$x=-\frac{9y}{5}+\frac{3}{10}$$

Solve for y

$y=-\frac{5x}{9}+\frac{1}{6}$