Question

$$y=\frac{x^{2}}{x+-1}$$

Solve for x (complex solution)

$x=\frac{-\sqrt{y\left(y-4\right)}+y}{2}$
$x=\frac{\sqrt{y\left(y-4\right)}+y}{2}$

Solve for x

$x=\frac{-\sqrt{y\left(y-4\right)}+y}{2}$
$x=\frac{\sqrt{y\left(y-4\right)}+y}{2}\text{, }y\geq 4\text{ or }y\leq 0$

Solve for y

$y=\frac{x^{2}}{x-1}$
$x\neq 1$