$$y = \frac { x ^ { 2 } - 3 } { 2 x - 1 }$$
$x=-\sqrt{y^{2}-y+3}+y$
$x=\sqrt{y^{2}-y+3}+y$
$y=-\frac{3-x^{2}}{2x-1}$
$x\neq \frac{1}{2}$
