Question

$$y=-(x+1) \left( { \left( \right) }^{ 2 } \right) _{ } { -3 }^{ }$$

Answer

$$x=-(y/^2_)/(-3)^()-1$$

Solution


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Divide both sides by \({()}^{2_()}\).
\[\frac{y}{{}^{2_}}=-(x+1){(-3)}^{}\]
Divide both sides by \({(-3)}^{}\).
\[\frac{\frac{y}{{}^{2_}}}{{(-3)}^{}}=-x-1\]
Add \(1\) to both sides.
\[\frac{\frac{y}{{}^{2_}}}{{(-3)}^{}}+1=-x\]
Multiply both sides by \(-1\).
\[-\frac{\frac{y}{{}^{2_}}}{{(-3)}^{}}-1=x\]
Switch sides.
\[x=-\frac{\frac{y}{{}^{2_}}}{{(-3)}^{}}-1\]