Question

$$y = ( \frac { 3 - 4 x } { x ^ { 2 } } ) =$$

Solve for x (complex solution)

$\left\{\begin{matrix}x=\frac{\sqrt{3y+4}-2}{y}\text{; }x=-\frac{\sqrt{3y+4}+2}{y}\text{, }&y\neq 0\\x=\frac{3}{4}=0.75\text{, }&y=0\end{matrix}\right.$

Solve for x

$\left\{\begin{matrix}x=\frac{\sqrt{3y+4}-2}{y}\text{; }x=-\frac{\sqrt{3y+4}+2}{y}\text{, }&y\neq 0\text{ and }y\geq -\frac{4}{3}\\x=\frac{3}{4}=0.75\text{, }&y=0\end{matrix}\right.$

Solve for y

$y=-\frac{4x-3}{x^{2}}$
$x\neq 0$