$$Y = \sin ^ { 2 } 4 x + \frac { 1 } { 2 } \cos \theta x$$
$Y=\frac{\cos(x\theta )-\cos(8x)+1}{2}$
$Y=\frac{-8\left(\sin(2x)\right)^{4}+\cos(x\theta )+8\left(\sin(2x)\right)^{2}}{2}$
