$$Y=\sin^{2}4x+\frac{1}{2}cos8x$$
$Y=\frac{1}{2}=0.5$
$x\in \mathrm{C}$
$Y = \frac{1}{2} = 0.5$
$Y=\frac{-16\left(\sin(x)\right)^{2}\left(\cos(x)\right)^{6}-16\left(\cos(x)\right)^{2}\left(\sin(x)\right)^{6}-2\left(\sin(2x)\right)^{4}+4\left(\sin(2x)\right)^{2}+1}{2}$
$x\in \mathrm{R}$
$Y = \frac{1}{2} = 0.5$