$$y= \sqrt{ { \left( \log_{ 10 }({ 10 }) \right) }^{ 2 } 2x-9 \times (5x-6- { x }^{ 2 } ) }$$
$x=\frac{\sqrt{36y^{2}-95}+43}{18}$
$x=\frac{-\sqrt{36y^{2}-95}+43}{18}\text{, }arg(y)<\pi \text{ or }y=0$
$x=\frac{\sqrt{36y^{2}-95}+43}{18}$
$x=\frac{-\sqrt{36y^{2}-95}+43}{18}\text{, }y\geq \frac{\sqrt{95}}{6}$
$y=\sqrt{9x^{2}-43x+54}$
