Question

$$Y= \tan { y }^{ 3 } \sqrt{ 3 }$$

Solve for Y

$Y=\sqrt{3}\tan(y^{3})$
$\nexists n_{1}\in \mathrm{Z}\text{ : }y=\frac{2^{\frac{2}{3}}}{2}\sqrt[3]{2\pi n_{1}+\pi }$

Solve for y

$y=\sqrt[3]{2\pi n_{1}+\arcsin(\frac{Y}{\sqrt{Y^{2}+3}})+\pi }\text{, }n_{1}\in \mathrm{Z}\text{, }\exists n_{3}\in \mathrm{Z}\text{ : }\left(n_{1}>\frac{2n_{3}-\frac{2\arcsin(\frac{Y}{\sqrt{Y^{2}+3}})}{\pi }-1}{4}\text{ and }n_{1}<\frac{2n_{3}-\frac{2\arcsin(\frac{Y}{\sqrt{Y^{2}+3}})}{\pi }+1}{4}\right)$
$y=\sqrt[3]{2\pi n_{2}+\arcsin(\frac{Y}{\sqrt{Y^{2}+3}})}\text{, }n_{2}\in \mathrm{Z}\text{, }\exists n_{3}\in \mathrm{Z}\text{ : }\left(n_{3}>\frac{4n_{2}+\frac{2\arcsin(\frac{Y}{\sqrt{Y^{2}+3}})}{\pi }-3}{2}\text{ and }n_{3}<\frac{4n_{2}+\frac{2\arcsin(\frac{Y}{\sqrt{Y^{2}+3}})}{\pi }-1}{2}\right)$