Question

$$y=x^{2}-6x+8$$

Solve for x (complex solution)

$x=\sqrt{y+1}+3$
$x=-\sqrt{y+1}+3$

Solve for x

$x=\sqrt{y+1}+3$
$x=-\sqrt{y+1}+3\text{, }y\geq -1$

Solve for y

$y=\left(x-4\right)\left(x-2\right)$