$$y=x2-4x+8$$
$x=\frac{x_{2}-y+8}{4}$
$$x_{2}-4x+8=y$$
$$-4x+8=y-x_{2}$$
$$-4x=y-x_{2}-8$$
$$-4x=-x_{2}+y-8$$
$$\frac{-4x}{-4}=\frac{-x_{2}+y-8}{-4}$$
$$x=\frac{-x_{2}+y-8}{-4}$$
$$x=\frac{x_{2}}{4}-\frac{y}{4}+2$$
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$x_{2}=4x+y-8$
$$x_{2}+8=y+4x$$
$$x_{2}=y+4x-8$$
