Question

$$y\ g=(\frac{1+\cos\ x}{1-\cos\ 2})^{\sqrt{x}}$$

Answer

$$y=(1+cos(x))^sqrt(x)/((1-cos(2))^sqrt(x)*g)$$

Solution


Use Division Distributive Property: \({(\frac{x}{y})}^{a}=\frac{{x}^{a}}{{y}^{a}}\).
\[yg=\frac{{(1+\cos{x})}^{\sqrt{x}}}{{(1-\cos{2})}^{\sqrt{x}}}\]
Divide both sides by \(g\).
\[y=\frac{\frac{{(1+\cos{x})}^{\sqrt{x}}}{{(1-\cos{2})}^{\sqrt{x}}}}{g}\]
Simplify  \(\frac{\frac{{(1+\cos{x})}^{\sqrt{x}}}{{(1-\cos{2})}^{\sqrt{x}}}}{g}\)  to  \(\frac{{(1+\cos{x})}^{\sqrt{x}}}{{(1-\cos{2})}^{\sqrt{x}}g}\).
\[y=\frac{{(1+\cos{x})}^{\sqrt{x}}}{{(1-\cos{2})}^{\sqrt{x}}g}\]