Solve y-120/[-45-\ overline 15-10 *(-18-15)\ ]

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Question

$$y-120\div[-45-\{\overline{15-10}\times(-18-15)\}]$$

$y-1$

Subtract $10$ from $15$ to get $5$.

$$y-\frac{120}{-45-conjugate(5)\left(-18-15\right)}$$

Complex conjugate of $5$ is $5$, the number with the same real part and the opposite imaginary part.

$$y-\frac{120}{-45-5\left(-18-15\right)}$$

Subtract $15$ from $-18$ to get $-33$.

$$y-\frac{120}{-45-5\left(-33\right)}$$

Multiply $5$ and $-33$ to get $-165$.

$$y-\frac{120}{-45--165}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $y$ times $\frac{-45--165}{-45--165}$.

$$\frac{y\left(-45--165\right)}{-45--165}-\frac{120}{-45--165}$$

Since $\frac{y\left(-45--165\right)}{-45--165}$ and $\frac{120}{-45--165}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{y\left(-45--165\right)-120}{-45--165}$$