Question

$$y - 7 = 1 \quad ( y = 8 )$$

Answer

b=1;y=8

Solution


Solve for \(y\) in \((y=8)\).
\[y=8\]
Substitute \(y=8\) into \(by-7=1\).
\[8b-7=1\]
Solve for \(b\) in \(8b-7=1\).
\[b=1\]
Therefore,
\[\begin{aligned}&b=1\\&y=8\end{aligned}\]