$$y(x)=-1/6 { x }^{ 3 }$$
$-\frac{x^{2}}{2}$
$$3\left(-\frac{1}{6}\right)x^{3-1}$$
$$-\frac{1}{2}x^{3-1}$$
$$-\frac{1}{2}x^{2}$$
Show Solution
Hide Solution
$-\frac{x^{3}}{6}$
$$-\frac{1}{6}x^{3}$$