$$y+4^{2}-4$$
$y+12$
$$y+16-4$$
$$y+12$$
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$1$
$$\frac{\mathrm{d}}{\mathrm{d}y}(y+16-4)$$
$$\frac{\mathrm{d}}{\mathrm{d}y}(y+12)$$
$$y^{1-1}$$
$$y^{0}$$
$$1$$