$$y + 6 \frac { 9 } { 16 } = - 3 \frac { 7 } { 24 }$$
$y = -\frac{473}{48} = -9\frac{41}{48} \approx -9.854166667$
$$48y+3\left(6\times 16+9\right)=-2\left(3\times 24+7\right)$$
$$48y+3\left(96+9\right)=-2\left(3\times 24+7\right)$$
$$48y+3\times 105=-2\left(3\times 24+7\right)$$
$$48y+315=-2\left(3\times 24+7\right)$$
$$48y+315=-2\left(72+7\right)$$
$$48y+315=-2\times 79$$
$$48y+315=-158$$
$$48y=-158-315$$
$$48y=-473$$
$$y=\frac{-473}{48}$$
$$y=-\frac{473}{48}$$
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