1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve y6+6-14 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$y6+6-14$$

Differentiate w.r.t. y_6

$1$

Steps Using Derivative Rule for Sum

Subtract $14$ from $6$ to get $-8$.

$$\frac{\mathrm{d}}{\mathrm{d}y_{6}}(y_{6}-8)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$y_{6}^{1-1}$$

Subtract $1$ from $1$.

$$y_{6}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

Show Solution

Evaluate

$y_{6}-8$

Show Solution

Example

Question

Differentiate w.r.t. y_6

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps