1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve y8+8-9 | Equatix

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Question

$$y8+8-9$$

Differentiate w.r.t. y_8

$1$

Steps Using Derivative Rule for Sum

Subtract $9$ from $8$ to get $-1$.

$$\frac{\mathrm{d}}{\mathrm{d}y_{8}}(y_{8}-1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$y_{8}^{1-1}$$

Subtract $1$ from $1$.

$$y_{8}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$1$$

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Evaluate

$y_{8}-1$

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Example

Question

Differentiate w.r.t. y_8

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps