$$z=(2+3i)i+(-y+2xi)$$
$y=-3+2i+2\xi -z$
$$z=-3+2i-y+2\xi $$
$$-3+2i-y+2\xi =z$$
$$-y+2\xi =z-\left(-3+2i\right)$$
$$-y=z-\left(-3+2i\right)-2\xi $$
$$-y=z+\left(3-2i\right)-2\xi $$
$$-y=z-2\xi +\left(3-2i\right)$$
$$\frac{-y}{-1}=\frac{z-2\xi +\left(3-2i\right)}{-1}$$
$$y=\frac{z-2\xi +\left(3-2i\right)}{-1}$$
$$y=-\left(z-2\xi +\left(3-2i\right)\right)$$
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$z=-\left(y-2\xi +\left(3-2i\right)\right)$
