$$z=(\frac{2+i}{3-i})^{2}$$
$z=\frac{1}{2}i=0.5i$
$$z=\left(\frac{\left(2+i\right)\left(3+i\right)}{\left(3-i\right)\left(3+i\right)}\right)^{2}$$
$$z=\left(\frac{5+5i}{10}\right)^{2}$$
$$z=\left(\frac{1}{2}+\frac{1}{2}i\right)^{2}$$
$$z=\frac{1}{2}i$$
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$z≔\frac{1}{2}i$
