$$z+6 \times (1/2) \frac{ 4 }{ }$$
$z+12$
$$z+\frac{6}{2}\times \frac{4}{1}$$
$$z+3\times \frac{4}{1}$$
$$z+3\times 4$$
$$z+12$$
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$1$
$$\frac{\mathrm{d}}{\mathrm{d}z}(z+\frac{6}{2}\times \frac{4}{1})$$
$$\frac{\mathrm{d}}{\mathrm{d}z}(z+3\times \frac{4}{1})$$
$$\frac{\mathrm{d}}{\mathrm{d}z}(z+3\times 4)$$
$$\frac{\mathrm{d}}{\mathrm{d}z}(z+12)$$
$$z^{1-1}$$
$$z^{0}$$
$$1$$