$$z ^ { 2 } + 1 , 4 z + 0 , 49$$
$196z\left(z^{2}+1\right)$
$$49=7^{2}$$
$$196z\left(z^{2}+1\right)$$
$$196z^{3}+196z$$
Show Solution
Hide Solution
$z^{2}+1,4z,49$