$$z^{2}+(\sqrt{3}+i)z+1=0; \Delta=(\sqrt{3}+i)^{2}-Y\cdot I\cdot1=$$
$z=\sqrt{3}\left(-\frac{1}{2}-\frac{1}{2}i\right)+\left(-\frac{1}{2}-\frac{1}{2}i\right)\approx -1.366025404-1.366025404i\text{, }\Delta =-IY+2+2\sqrt{3}i\text{, }Y\in \mathrm{C}\text{, }I\in \mathrm{C}$
$z=\sqrt{3}\left(-\frac{1}{2}+\frac{1}{2}i\right)+\left(\frac{1}{2}-\frac{1}{2}i\right)\approx -0.366025404+0.366025404i\text{, }\Delta =-IY+2+2\sqrt{3}i\text{, }Y\in \mathrm{C}\text{, }I\in \mathrm{C}$
