Question

$$z^{4}-(5-14iz^{2}-2(5+12i=0$$

Solve for c

$c=z^{4}+\left(-5+14i\right)z^{2}+\left(-10-2i\right)$

Show Solution

Solve for z

$z=\frac{\sqrt{-2\sqrt{4c+\left(-131-132i\right)}+\left(10-28i\right)}}{2}$
$z=-\frac{\sqrt{-2\sqrt{4c+\left(-131-132i\right)}+\left(10-28i\right)}}{2}$
$z=-\frac{\sqrt{2\sqrt{4c+\left(-131-132i\right)}+\left(10-28i\right)}}{2}$
$z=\frac{\sqrt{2\sqrt{4c+\left(-131-132i\right)}+\left(10-28i\right)}}{2}$