Question

$$z^{n}=2i$$

Solve for n

$n=\frac{2\pi n_{1}i}{\ln(z)}+\frac{2\ln(2)+\pi i}{2\ln(z)}$
$n_{1}\in \mathrm{Z}$
$z\neq 1\text{ and }z\neq 0$

Solve for z

$z=e^{-\frac{2\pi n_{1}iRe(n)}{\left(Re(n)\right)^{2}+\left(Im(n)\right)^{2}}-\frac{2\pi n_{1}Im(n)}{\left(Re(n)\right)^{2}+\left(Im(n)\right)^{2}}+\frac{\pi \left(Im(n)+iRe(n)\right)}{2\left(\left(Re(n)\right)^{2}+\left(Im(n)\right)^{2}\right)}}\times 2^{\frac{Re(n)-iIm(n)}{\left(Re(n)\right)^{2}+\left(Im(n)\right)^{2}}}$
$n_{1}\in \mathrm{Z}$