Resolver 16+[\ +(-3)]=[16+(-2)]+(-3) (d) 147+(\ )=0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$16 + [ \quad + ( - 3 ) ] = [ 16 + ( - 2 ) ] + ( - 3 ) 147 + ( - 0 )$$