Resolver (150(3) + 112.5(2) + 150(m) + 120(4))/(3 + 2 + m + 4) = 127 * 5 | Equatix - Math Solver

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

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Question

$$\frac{150(3)+112.5(2)+150(m)+120(4)}{3+2+m+4}=127\cdot5$$