Cómo resolver 19:33 82% Search Mathful mathful.com Mathful x ^ 2 + y ^ 2 + 6x + 8y + 8 = 0 Answer from Mathful To solve this equation, we can start by completing the square for the x-terms and the y-terms separately. For x-terms: Rearrange the equation: x ^ 2 + 6x + y ^ 2 + 8y + 8 = 0 . Add (6/2) ^ 2 = 9 to both sides to complete the square: x ^ 2 + 6x + 9 + y ^ 2 + 8y + 8 = 9 . Simplify: (x + 3) ^ 2 + y ^ 2 + 8y + 17 = 9 . For y-terms : Rearrange the equation: (x + 3) ^ 2 + y ^ 2 + 8y + 17 = 9 . Add (8/2) ^ 2 = 16 to both sides to complete the square: (x + 3) ^ 2 + y ^ 2 + 8y + 16 + 17 = 9 + 16 Simplify: (x + 3) ^ 2 + (y + 4) ^ 2 + 33 = 25 . The equation is now in the form of (x - h) ^ 2 + (y - k) ^ 2; =r^ ^ 2 , where the center is (- 3, - 4) and the radius squared is 25. Didn't find the question you wanted?

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1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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