Cómo resolver = a sin 1-2 sin =1-(1-cos 2 alpha)sin^ 2 beta= 1-sin alpha sin sin alpha sin alpha sin alpha sin alpha sin alpha sin alpha sin alpha sin alpha sin^ 2 beta+csin alpha; ^ 2 A-cos^ 2 A cos 2B=sin^ 2 R-cos^ 2 R cos 2A

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1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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