हल करना (b) (-3)+(-20)=(-2; 16+[\ +(-3)]=[16+(-2)]+(-3) (d ) 147+(\ )=0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$16 + 1 \quad + ( - 31 ) - [ 16 + ( - 21 ] + ( - 3 ) + ( - 3 ) + ( - 20 ) - ( - 2 )$$