$$| \begin{array} { l } { 9 } \\ { 14 ( - 10 x + 5 ) = 3 ( x + 9 ) - 10 } \\ { 14 - 1 x - 5 = 3 x + 27 - 10 } \end{array} | \begin{array} { l } { 10 } \\ { 5 } \end{array}$$
