हल करना (cos(pi + x) * cos(- x))/(sin(pi - x) * cos(pi/2 + x)) = cot^2 x | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{\cos(\pi+x)\cos(-x)}{\sin(\pi-x)\cos(\frac{\pi}{2}+x)}=\cot^{2}x$$