कैसे हल करें Solve the following quadratic equations by transforming them into first squares . x ^ 2 + x - 6 = 0 ( ii) 2x ^ 2 - 9x + 4 = 0 ) 14x ^ 2 + x - 3 = 0 ( iv) 3x ^ 2 - 32x + 12 = 0 ( v) x ^ 2 + 2px - 3qx - 6pq = 0 vi) sqrt(3) * x ^ 2 + 10x + 8sqrt(3) = 0 ( vii) 25x ^ 2 + 30x + 7 = 0 viii) 3a ^ 2 * x ^ 2 + 8abx + 4b ^ 2 = 0; (a ne0) ( ix) x ^ 2 + ax + b = 0 ( x) x ^ 2 + bx = a ^ 2 - ab

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1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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