कैसे हल करें Verify whether the values of x given in each case are the zeroes of the polynomial or not ?. ) p(x) = 2x + 1 ; x = - 1/2 ) p(x) = 5x - pi ) p(x) = x ^ 2 - 1 ; x = plus/minus 1 ( iv) p(x) = (x - 1)(x + 2); x = - 1 , -2 x = - 3/2 ( v) p(y) = y ^ 2; y = 0 ( vi) p(x) = ax + b ; x = - b/a; x = 1/2, - 1/2; f(x) = 3x ^ 2 - 1 ; x = - 1/(sqrt(3)); 2/(sqrt(3)) ( viii) f(x) = 2x - 1 , the zero of the polynomial in each of the following cases.

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1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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