कैसे हल करें 4 Express sqrt(3) * sin x + cos x in the form r * sin(x + alpha) where r 0 and 0

Q: कैसे हल करें 4 Express sqrt(3) * sin x + cos x in the form r * sin(x + alpha) where r > 0 and 0 <= alpha <= pi/2 Solve the equation |sqrt(3) * sin x + cos x| = sqrt(3) for 0 <= x <= 2pi Sketch the graph of |sqrt(3) * sin x + cos x| for 0 <= x <= 2pi Hence, find the set of values of x, in the interval 0 <= x <= 2pi which satisfy the inequality |sqrt(3) * sin x + cos x| >= sqrt(3) 5 Express cos x + sin x in the form r * cos(x - alpha) where r > 0 and 0 <= alpha <= pi

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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कैसे हल करें 4 Express sqrt(3) * sin x + cos x in the form r * sin(x + alpha) where r > 0 and 0 <= alpha <= pi/2 Solve the equation |sqrt(3) * sin x + cos x| = sqrt(3) for 0 <= x <= 2pi Sketch the graph of |sqrt(3) * sin x + cos x| for 0 <= x <= 2pi Hence, find the set of values of x, in the interval 0 <= x <= 2pi which satisfy the inequality |sqrt(3) * sin x + cos x| >= sqrt(3) 5 Express cos x + sin x in the form r * cos(x - alpha) where r > 0 and 0 <= alpha <= pi

Accepted Answer

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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