हल करना (160 + 2) ^ 2 = 106 ^ 2 * \{5(166 + 2 ^ 2) + 7(66 + 2 ^ 2) + 7 ^ 2\} | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(160+2)^{2}=106^{2}\{5(166+2^{2})+7(66+2^{2})+7^{2}\}$$