हल करना x ^ 2 + 4x + 4y ^ 2 - 8y + 4 = 0; (x ^ 2 + 4x) + y(y ^ 2 + 2y) = - 4 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$x^{2}+4x+4y^{2}-8y+4=0; (x^{2}+4x)+y(y^{2}+2y)=-4$$