$$\frac{5}{x-1}+\frac{1}{y-2}=2;\frac{6}{x-1}=\frac{3}{y-2}; \frac{1}{x}+\frac{5}{y}=7;\frac{3}{x}+\frac{4}{y}-5; \frac{1}{x-y}+\frac{1}{x+y}=3;\frac{2}{x+y}-\frac{3}{x+y}=$$
