Bagaimana menyelesaikan Obtain a particular solution of each of the following equations using the annihilator method. i) y^ prime prime +4y=cos 3x ) y^ prime prime +y^ prime +y=x^ 2 ) y^ prime prime -3y^ prime +2y=x e^ x +e^ 2x +x^ 3 e^ -x 2013 iv) y^ prime prime prime +y=x^ 2 e^ -x sin x; y^ prime prime prime -y=x e^ x cos x vi) y^ prime prime prime +y^ prime prime +y^ prime +y=(1+x+x^ 2 )cos x+x cos h x vii) y^ prime prime -2i y^ prime -y=x sin h x 2014 -68

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1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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